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Mole Ratio: Definition, Determination, Unit, and Problems - Testbook

Last Updated on Feb 17, 2025
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Defining the Mole Ratio

The mole ratio is the ratio of the quantities in moles of any two compounds involved in a chemical reaction that is balanced. The balanced chemical equation provides the ratios of the molecules necessary to complete the reaction. It's important to note that mole ratios cannot be calculated for an unbalanced equation. Mole ratios serve as conversion factors between products and reactants in many chemistry problems.

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Defining a Mole

In the realm of chemistry, a mole is a fundamental unit used to measure the amount of a substance, often referred to as the chemical amount.

A mole is defined as the amount of a substance that contains exactly 6.022 x 10 23 ‘elementary entities’ of the given substance.

Each mole contains 6.023 x 10 23 units. These units can be atoms, molecules, ions, electrons, or any other entities.

Examples include:

  • 1 mole of helium atoms = 6.023 x 10 23 helium atoms
  • 1 mole of oxygen molecules = 6.023 x 10 23 oxygen molecules.
  • 1 mole of electrons = 6.023 x 10 23 electrons.
  • 1 mole of potassium ions = 6.023 x 10 23 potassium ions.

How much does one mole weigh?

The mass of one mole atom of any element is exactly equal to the atomic mass in grams of that element.

Similarly, the mass of 1 mole molecule of any substance is equal to its molecular mass in grams or gram molecular mass .

Examples:

  • Mass of 1 mole helium atom = 4 g
  • Mass of 1 mole of oxygen molecule = 32 g
  • Mass of 1 mole of carbon atom = 12 g
  • Mass of 1 mole of water (H 2 O) molecule = 18 g

∴ Mole of the substance = (Mass of the substance in gm / Gram molecular mass of that substance)

For more information, check out this article on the Mole concept

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Determining Mole Ratio in Stoichiometric Reactions

Stoichiometry is a crucial concept in chemistry that allows us to use balanced chemical equations to calculate the amounts of reactants and products. In this process, we use ratios from the balanced equation. All reactions are dependent on one main factor, the amount of substance present. We cannot calculate the mole ratio for an unbalanced equation.

1. Consider a balanced chemical equation

H 2 + ½O 2 → H 2 O

  • The coefficients of H 2 =1
  • The coefficients of O 2 = ½
  • The coefficients of H 2 O = 1

These coefficients provide the molecular information for the chemical equation.

In this chemical equation 1 mole of hydrogen (H 2 ) reacts with ½ mole of oxygen (O 2 ) to produce 1 mole of water (H 2 O) .

To determine the mole ratio of any two components of the equation, compare the coefficients of each component in the equation.

  • Mole ratio between H 2 and O 2 = ( 1 mole of H 2 / ½ mole of O 2 ) = 2:1
  • Mole ratio between H 2 and H 2 O = ( 1 mole of H 2 / 1 mole of H 2 O) = 1:1
  • Mole ratio between O 2 and H 2 O = ( ½ mole of O 2 / 1 mole of H 2 O) = 1:2

Unit of Mole Ratio

The mole ratio is a dimensionless unit . This is because it is expressed in mole:mole, and the units of moles cancel each other out.

Practicing Mole Ratio Problems

1. Given the reaction 2Al + 3Br2 → 2AlBr3, how many moles of AlBr3 are produced from 1.5 moles of Al?

2. How many moles of water are produced when 2.5 moles of oxygen react with an excess of hydrogen in the reaction 2H2 + O2 → 2H2O?

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Frequently Asked Questions

A mole ratio is the ratio between the amounts in moles of any two compounds involved in a balanced chemical reaction.

In the balanced chemical equation of ammonia is N2 + 3H2 → 2NH3, the mole ratio between N2 and H2 is 1:3.

In the balanced chemical equation of zinc to sulfuric acid is Zn + H2SO4 → ZnSO4 + H2, the mole ratio between Zn and H2SO4 is = 1:1.

Mole ratios allow comparison of the amounts of any two materials in a balanced equation. Calculations can be made to predict how much product can be obtained from a given number of moles of reactant.

Stoichiometry is an important concept in chemistry that helps us use balanced chemical equations to calculate amounts of reactants and products. Here, we can use mole ratios from the balanced equation.

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