Surveying MCQ Quiz - Objective Question with Answer for Surveying - Download Free PDF
Last updated on May 15, 2025
Latest Surveying MCQ Objective Questions
Surveying Question 1:
The value of the smallest division of the circle of a repeating theodolite is 10 minutes. what is the suitable vernier to read up to 10 seconds?
Answer (Detailed Solution Below)
Surveying Question 1 Detailed Solution
Concept:
Least count = \(\frac{S}{n}\)
n → no. of divisions on vernier scale
s → smallest division of main scale
Calculation:
s = 10’ = 10 minutes
L.C = 10” = \(\frac{{10'}}{{60}} = \frac{1}{{6}}\) minutes
\(\frac{1}{{6}} = \frac{{10}}{n}\)
n = 10 × 6
n = 60
Surveying Question 2:
In which direction is the zero marked in the ring of the prism compass?
Answer (Detailed Solution Below)
Surveying Question 2 Detailed Solution
Concept:
Prismatic compass:
- The graduated ring is attached to the needle and does not rotate with the line of sight.
- The graduations have 0 at S, 90° at W, 180° at N, and 270° at E.
- Graduations are engraved inverted since the graduated ring is read through the prism.
- The readings are taken with the help of a prism provided at the eye vane.
- Sighting and reading can be done simultaneously.
- The instrument can be held in hand also while making the observations.
- The eye vane consists of a metal vane with large silt.
Additional Information
- The graduations have 0 at N and S, 90° at East and West in the surveyor compass.
Surveying Question 3:
In the given image, Read the observation carefully which was taken during the testing of a dumpy level.
Instrument at P |
Staff reading on |
|
P |
Q |
|
P |
1.543 |
2.123 |
Q |
1.121 |
1.750 |
Answer (Detailed Solution Below)
Surveying Question 3 Detailed Solution
Concept:
True difference is given by the following formula:
TD = (δhPQ when instrument is at Q + δhPQ when instrument is at P)/2
where,
TD = True Difference
δhPQ = Apparent difference in elevation between P and Q
Calculation:
When the instrument is at P, apparent height difference = 2.123 - 1.543 = 0.58
When the instrument is at Q, apparent height difference = 1.750 - 1.121 = 0.629
So,
\(TD = \frac{{0.629 + 0.58}}{2} = 0.6045\)
Now, doing the adjustment,
When the instrument is at Q, staff reading at Q = 1.750
So, Adjusted reading = 1.750 - TD = 1.750 - 0.6045 = 1.1455 = 1.146 m
Surveying Question 4:
Which of the survey work can neither be done in bad weather nor suitable for large and precise work but is adopted because chances of getting omission of any detail are least?
Answer (Detailed Solution Below)
Surveying Question 4 Detailed Solution
Concept:
Plane table survey:
A plane table surveying is a graphical method of surveying. In this method of surveying, field observation and plotting are done simultaneously helping the surveyor to compare the plotted details with actual features of the ground.
Advantages of Plane Table Survey:
- It is suitable for the location of details as well as contouring for large-scale maps directly in the field.
- As surveying and plotting are done simultaneously in the field, chances of getting omission of any detail get less.
- The plotting details can immediately get compared with the actual objects present in the field. Thus errors, as well as the accuracy of the plot, can be ascertained as the work progresses in the field.
- The plane table survey is generally more rapid and less costly than most other types of survey.
Disadvantages of Plane Table Survey:
- The plane table survey is not possible in unfavorable climates such as rain, fog, etc.
- This method of survey is not very accurate and thus unsuitable for large scale or precise work.
- As no field book is maintained, plotting at different scale require full exercise.
- The quality of the final map depends largely on the drafting capability of the surveyor.
Important Points
The setting of Instruments:
- Fixing
- Leveling
- Centering
Different methods for plane table survey:
- Radiation
- Intersection
- Traversing
- Resection
Surveying Question 5:
For exact centering of plane table, which of the following instrument is used?
Answer (Detailed Solution Below)
Surveying Question 5 Detailed Solution
Explanation:
Plumb bob and plumb fork:
- A plumbing fork is a hairpin-shaped brass frame made of arms of equal length.
- One is horizontal (upper arm) has a pointed end and is kept over the drawing sheet touching the plotted position of the instrument station while the other is inclined at a certain angle(lower arm) has a hook from which plumb bob is suspended as shown in the figure.
∴ Hence accurate centering of the plane table is done by using a plumbing fork.
Additional Information
Alidade:
- It is an instrument used in plane table surveys.
- It is a wooden or brass ruler of about 50-60 cm in length. It is also known as the sight rule.
- Two vanes, the “object vane” and the “sight vane” are hinged at their two ends.
Spirit level (Bubble tube):
- It is an instrument used in leveling.
- The glass tube containing the liquid and bubbles at a spirit level. In leveling, it is used to check the accuracy of the horizontal surface.
Important Points
The Basic surveying instruments required for plane table surveying are:
- Plane table
- Alidade for sighting (telescopic or simple)
- Plumb bob and plumb fork
- Compass
- Spirit level
- Chain
- Ranging rods
- Tripod
- Drawing sheet and drawing tools
Top Surveying MCQ Objective Questions
Instrument used for measuring area on a contour map is
Answer (Detailed Solution Below)
Surveying Question 6 Detailed Solution
Download Solution PDFThe different types of area measuring devices are as follows:
1. Clinometer or Inclinometer: It is used to measure angles of slopes either elevation or depression of an object with respect to gravity direction as reference.
2. Planimeter: It is the mechanical device used to measure area of plane. This measurement consists of dragging along boundary region.
3. Graphometer: It is semi-circular surveying instrument used to measure angles.Which one of the following survey is used to define the property line?
Answer (Detailed Solution Below)
Surveying Question 7 Detailed Solution
Download Solution PDFExplanation:
Cadastral survey: Cadastral survey are made incident to the fixing of property lines, the calculation of land area, or the transfer of land property from one owner to another. They are also made to fix the boundaries of municipalities and of state and federal jurisdictions.
Topographical survey: This consist of horizontal and vertical location of certain points by linear and angular measurements and is made to determine the natural features of a country such as rivers, streams, lakes, woods, hills etc and such artificial features like roads, railways etc.
City survey: They are made in connection with the construction of streets, water supply systems, sewers and other works.
Topographical, cadastral and city survey are the parts of Land surveying.
A 50 m tape is held 2 m out of line. What is the true length?
Answer (Detailed Solution Below)
Surveying Question 8 Detailed Solution
Download Solution PDFConcept:
The correction due to the wrong alignment of the chain is given by
\({\rm{C}} = \frac{{{{\rm{d}}^2}}}{{2 \;\times\; {\rm{L}}}}\)
d - Difference in elevation due to the wrong alignment
L - The sloping length
l - True length
Correction due to the wrong alignment of the chain is always negative
True length = Measured length - Correction
Calculation:
Given: d = 2 m, L = 50 m
\({\rm{C}} = \frac{{{{\rm{2}}^2}}}{{2 \;\times\; {\rm{50}}}}\)
⇒ C = 0.04
True length (l) = 50 - 0.04 = 49.96 m.
The permissible error (E) for the Precise levelling type with distance (D) in kilometre is given by:
Answer (Detailed Solution Below)
Surveying Question 9 Detailed Solution
Download Solution PDFConcept:
The precision of leveling is ascertained according to the error of closure. The permissible limit of closing error depends upon the nature of the work for which the leveling is to be done. The permissible closing error may be expressed as, \(\text{E} = \text{C}\times\sqrt{D}\)
Where,
E = the error in metres,
C = the constant, the value of which depends upon the type of instrument, nature of the country, atmospheric conditions and care and judgement of the level man
D = distance in kilometre
- Rough levelling: \(\text{E} = \pm\text{0.100}\times\sqrt{D}\)
- Ordinary levelling: \(\text{E} = \pm\text{0.025}\times\sqrt{D}\)
- Accurate levelling: \(\text{E} = \pm\text{0.012}\times\sqrt{D}\)
- Precise levelling: \(\text{E} = \pm\text{0.006}\times\sqrt{D}\)
Which of the following types of chain consists of 16 links, where each link being \(2\frac{1}{16}\) ft long?
Answer (Detailed Solution Below)
Surveying Question 10 Detailed Solution
Download Solution PDFExplanation:
Given Link length = \(2\frac{1}{16}\) ft
Chain has 16 Links ⇒ Total Length = 16 × \(2\frac{1}{16}\) = 33 ft
Revenue Chain:
The revenue chain is 33 ft long and consists of 16 links.
Additional InformationThese chains are mainly used for measuring field in cadastral survey.
Types of chain |
Length |
No. of links |
Length of one link |
Meter chain |
20 m or 30 m |
100 or 150 |
20 cm |
Engineering chain |
100 ft |
100 |
1 ft |
Gunter chain |
66 ft |
100 |
0.66 ft |
Revenue chain |
33 ft |
16 |
2 and 1/16 ft |
The lines joining points of equal dip are called
Answer (Detailed Solution Below)
Surveying Question 11 Detailed Solution
Download Solution PDFConcept:
Dip:
- It is the inclination of the magnetic needle with the horizontal. The dip is zero at the equator and the needle will remain horizontal.
- At a place near 70° north latitude and 96° west longitude, the dip will be 90°. This area is called the magnetic north pole. Similarly, near the south magnetic pole, the dip is 90°.
Declination:
- It is the angle between the magnetic and geographic meridians or the angle in the horizontal plane between magnetic north and true north.
Explanation:
Magnetic Lines |
Definition |
Agonic Line |
The line joining the places of zero declination. |
Aclinic Line |
The line joining the places of zero dip |
Isoclinic Line |
The line joining the places of the same dip |
Isogonic lines |
Isogonic are the lines joining points of equal declination at a time of observation. |
If the bearing of the side AB of a regular hexagon traverse ABCDEFA shown in the figure is 36°45', the bearing of the adjacent side BC of the traverse is:
Answer (Detailed Solution Below)
Surveying Question 12 Detailed Solution
Download Solution PDFExplanation:
The difference (degree) in the magnitude of the fore bearing and back bearing of any line is 180° or if the difference is exactly 180°, the two stations may be considered as not affected by local attraction.
For regular hexagon, Sum of interior angles = (n - 2)180°
Sum of interior angles = (6 - 2)180° = 720°
Each interior angle = \(\frac{720}{6}\) = 120°
Back bearing = 180° + Fore bearing = 180° + 36°45' = 216°45'
∴ Fore bearing of BC = 216°45' - 120° = 96°45'
Which of following is the least count of leveling staff?
Answer (Detailed Solution Below)
Surveying Question 13 Detailed Solution
Download Solution PDFExplanation:
Leveling staff:
- It is a self-reading graduated wooden rod having a rectangular cross-section. The lower end of the rod is shod with metal to protect it from wear and usually point of zero measurements from which the graduations are numbered.
- Staff are either solid (having a single piece of 3-meter height) or folding staff (of 4-meter height into two or three pieces)
- The least count of a leveling staff is 5 mm.
- Leveling used with a leveling instrument to determine the difference in height between points or heights of points above a vertical datum.
Important Points
Instrument | Least count |
Vernier theodolite | 20 second |
Optical theodolite | 1 second |
Prismatic compass | 30 minute |
Surveyor compass | 15 minute |
In plane surveying where a graduated staff is observed either with horizontal line of sight or inclined line of sight, the effect of refraction is to
Answer (Detailed Solution Below)
Surveying Question 14 Detailed Solution
Download Solution PDFDue earth refraction, line of sight bends towards the earth, therefore we noted less value of staff of reading i.e. Decrease in staff reading. To understand this refers the following figure:
Instrument
SR1 = Staff reading without refraction
SR2 = staff reading with refraction (Noted value)
It is clear from above that: SR2 < SR1
∴ Staff reading reduces due to refraction.
Important Point:
Phenomena |
Staff Reading |
Reduced Level |
Refraction |
Decrease |
Increases |
Earth’s Curvature |
Increase |
Decrease |
Calculate the number of division of the main scale that is equal to the 8 divisions of the extended vernier.
Answer (Detailed Solution Below)
Surveying Question 15 Detailed Solution
Download Solution PDFConcept:
Vernier Scale is used to measure the fractional part of the least division marked on the main scale.
Types of Vernier Scale
- Direct Vernier:
- N divisions of the direct vernier = (N - 1) division of the main scale
- Retrograde Vernier:
- N divisions of the retrograde vernier = (N + 1) division of the main scale
- Extended Vernier:
- N divisions of the extended vernier = (2 N - 1) division of the main scale
Calculation:
N divisions of the extended vernier = (2 N - 1) division of the main scale
8 divisions of the extended vernier = (2 × 8 - 1) division of the main scale
8 divisions of the extended vernier = 15 division of the main scale