निम्नलिखित को हल कीजिए:

sin 2x + 2 sin 4x + sin 6x 

This question was previously asked in
SSC CGL 2023 Tier-I Official Paper (Held On: 18 Jul 2023 Shift 2)
View all SSC CGL Papers >
  1. 4 cos2× sin 4x
  2. 4 cos2​× sin x
  3. 2 cos2​× sin 4x
  4. 4 sin2​× sin 4x

Answer (Detailed Solution Below)

Option 1 : 4 cos2× sin 4x
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PYST 1: SSC CGL - English (Held On : 11 April 2022 Shift 1)
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25 Questions 50 Marks 12 Mins

Detailed Solution

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दिया गया है:

sin 2x + 2 sin 4x + sin 6x 

प्रयुक्त सूत्र:

sin C + sin D = 2 × sin (C + D)/2 × cos (C - D)/2

cos 2θ = (2 × cos2 θ  - 1)

गणना:

sin 6x + sin 2x + 2 sin 4x

⇒ 2 × sin (6x + 2x)/2 × cos (6x - 2x)/2 + 2 sin 4x

⇒ 2 × sin 4x × cos 2x + 2 sin 4x

⇒ 2 × sin 4x (cos 2x + 1)

⇒ 2 × sin 4x {(2 × cos2x - 1) + 1) }

⇒ (2 × sin 4x) × (2 × cos2 x) 

⇒ 4 cos2 ×  sin 4x

∴ सही उत्तर 4 cos2 × sin 4x है

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