Question
Download Solution PDFयदि 10 cm त्रिज्या के एक ठोस गोले को पिघलाकर समान त्रिज्या की 8 गोलाकार ठोस गेंदें बनाई जाती हैं, तो ऐसी प्रत्येक गेंद का पृष्ठीय क्षेत्रफल कितना होगा? [π =\(\frac{{22}}{7}\) का प्रयोग कीजिए।]
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया:
आर = 10 सेमी
प्रयुक्त सूत्र:
आयतन = 4/3 x 22/7 x R x R x R
पृष्ठीय क्षेत्रफल (गोलाकार)= 4 x 22/7 x r x r
समाधान:
बड़े गोले का आयतन = 4/3 x 22/7 x 103
हमारे पास समान त्रिज्या के 8 छोटे गोले हैं
छोटे गोले का आयतन = 4/3 x 22/7 x r3
बड़े गोले का आयतन = 8 × छोटे गोले का आयतन
4/3 x 22/7 x 103 = 8 × 4/3 x 22/7 x r3
⇒ r3 = 1000/8
⇒ r = 5 सेमी
पृष्ठीय क्षेत्रफल (गोलाकार) = 4 x 22/7 x 52
= 88/7 x 25
= 314.285714 = 314 \(2\over7\) सेमी 2
Last updated on Jun 2, 2025
-> The RRB NTPC Admit Card 2025 has been released on 1st June 2025 on the official website.
-> The RRB Group D Exam Date will be soon announce on the official website. Candidates can check it through here about the exam schedule, admit card, shift timings, exam patten and many more.
-> A total of 1,08,22,423 applications have been received for the RRB Group D Exam 2025.
-> The RRB Group D Recruitment 2025 Notification was released for 32438 vacancies of various level 1 posts like Assistant Pointsman, Track Maintainer (Grade-IV), Assistant, S&T, etc.
-> The minimum educational qualification for RRB Group D Recruitment (Level-1 posts) has been updated to have at least a 10th pass, ITI, or an equivalent qualification, or a National Apprenticeship Certificate (NAC) granted by the NCVT.
-> This is an excellent opportunity for 10th-pass candidates with ITI qualifications as they are eligible for these posts.
-> The selection of the candidates is based on the CBT, Physical Test, and Document Verification.
-> Prepare for the exam with RRB Group D Previous Year Papers.