The function f(x) is defined by f(x)={|x|x0,,x0x=0 then, at x = 0 it is

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UP TGT Mathematics 2019 Official Paper
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  1. Continuous
  2. Discontinuous at x = 0 and has discontinuity of first kind
  3. Discontinuous at x = 0 and has removable discontinuity
  4. Discontinuous at x = 0 and has discontinuity of second kind

Answer (Detailed Solution Below)

Option 2 : Discontinuous at x = 0 and has discontinuity of first kind
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Detailed Solution

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Concept:

f(x) is continuous at x = a, if LHL = RHL = f(a)

 limxaf(x)=limxa+f(x)=limxaf(x)

 f(x) is differentiable if LHD = RHD

LHD=limh0f(ah)f(a)hRHD=limh0+f(a+h)f(a)h

Discontinuity of the First Kind: A function f(x) is said to have a discontinuity of the first kind from the right at x = a if the right hand of the function exists but not equal to f(a).

Discontinuity of the Second Kind: A function f(x) is said to have discontinuity of the second kind at x = a, if neither left-hand limit of f(x) at x = a nor right-hand limit of f(x) at x = a exists.

Removable Discontinuity: A function f(x) is said to have a removable discontinuity at x = a if the left-hand limit at x tends to point ‘a’ is equal to the right-hand limit at x tends to point ‘a’ but their common value is not equal to f(a). 

Calculation:

f(x)={|x|x0,,x0x=0

For x ≠ 0,

f(x) = -x/x = -1,   if x < 0

f(x) = x/x = 1. if x > 0

Now,

LHL = limx0f(x)=limx0x/x=1

RHL = limx0+f(x)=limx0+x/x=1

limx0f(x)=0

Since,

LHL ≠ RHL we can say that the function is not continuous at x = 0

Only x = 0, is the point of discontinuity. 

Based on the definition, the function has discontinuity of the first kind. 

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