Question
Download Solution PDFఒక శంకువు 32 సెం.మీ ఎత్తు మరియు దాని ఆధార వ్యాసార్థం 8 సెం.మీ. దానిని కరిగించి ఒక గోళంగా తిరిగి తయారు చేస్తే, గోళం యొక్క వ్యాసార్థం కనుగొనండి.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFమనకు తెలిసినట్లుగా,
శంకువు ఘనపరిమాణం = 1/3 x πR2h
గోళం ఘనపరిమాణం = (4/3) πr3
శంకువు వ్యాసార్థం r = 8 సెం.మీ మరియు శంకువు ఎత్తు h = 32 సెం.మీ
ప్రశ్న ప్రకారం
⇒ (4/3) x πR3 = 1/3 x π x 8 x 8 x 32
⇒ R3 = (8 x 8 x 32 x 3)/(3 x 4)
⇒ R3 = 8 x 8 x 8
⇒ R = 8 సెం.మీ
∴ గోళం యొక్క వ్యాసార్థం 8 సెం.మీ.
Last updated on Jul 2, 2025
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