Question
Download Solution PDFएक शंकू 32 सेमी उंच आहे आणि त्याच्या पायाची त्रिज्या 8 सेमी आहे. ते वितळले जाते आणि गोलाकार बनवले जाते. गोलाची त्रिज्या शोधा.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFजसे आपल्याला माहित आहे,
शंकूची मात्रा = 1/3 × πR 2 h
गोलाची मात्रा = (4/3) πr 3
शंकूची त्रिज्या r = 8 सेमी आणि शंकूची उंची h = 32 सेमी
प्रश्नानुसार
⇒ (4/3) × πR 3 = 1/3 × π × 8 × 8 × 32
⇒ आर ३ = (८ × ८ × ३२ × ३)/(३ × ४)
⇒ R 3 = 8 × 8 × 8
⇒ R = 8 सेमी
∴ गोलाची त्रिज्या 8 सेमी आहे.
Last updated on Jul 2, 2025
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