Question
Download Solution PDFA cone is 32 cm high and the radius of its base is 8 cm. It is melted and recast into a sphere. Find the radius of the sphere.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFAs we know,
Volume of cone = 1/3 × πR2h
Volume of sphere = (4/3) πr3
Radius of cone r = 8 cm and Height of cone h = 32 cm
According to the question
⇒ (4/3) × πR3 = 1/3 × π × 8 × 8 × 32
⇒ R3 = (8 × 8 × 32 × 3)/(3 × 4)
⇒ R3 = 8 × 8 × 8
⇒ R = 8 cm
∴ Radius of sphere is 8 cm.
Last updated on Jul 2, 2025
-> The RRB JE CBT 2 Result 2025 has been released for 9 RRBs Zones (Ahmedabad, Bengaluru, Jammu-Srinagar, Kolkata, Malda, Mumbai, Ranchi, Secunderabad, and Thiruvananthapuram).
-> RRB JE CBT 2 Scorecard 2025 has been released along with cut off Marks.
-> RRB JE CBT 2 answer key 2025 for June 4 exam has been released at the official website.
-> Check Your Marks via RRB JE CBT 2 Rank Calculator 2025
-> RRB JE CBT 2 admit card 2025 has been released.
-> RRB JE CBT 2 city intimation slip 2025 for June 4 exam has been released at the official website.
-> RRB JE CBT 2 Cancelled Shift Exam 2025 will be conducted on June 4, 2025 in offline mode.
-> RRB JE CBT 2 Exam Analysis 2025 is Out, Candidates analysis their exam according to Shift 1 and 2 Questions and Answers.
-> The RRB JE Notification 2024 was released for 7951 vacancies for various posts of Junior Engineer, Depot Material Superintendent, Chemical & Metallurgical Assistant, Chemical Supervisor (Research) and Metallurgical Supervisor (Research).
-> The selection process includes CBT 1, CBT 2, and Document Verification & Medical Test.
-> The candidates who will be selected will get an approximate salary range between Rs. 13,500 to Rs. 38,425.
-> Attempt RRB JE Free Current Affairs Mock Test here
-> Enhance your preparation with the RRB JE Previous Year Papers.