[(ka)b-c × (kb)c-a × (kc)a-b] × (x0 - 1) का मान क्या है?

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RRB Group D 17 Sept 2022 Shift 3 Official Paper
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  1. 1
  2. a + b + c
  3. 0
  4. abc

Answer (Detailed Solution Below)

Option 3 : 0
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गणना:

प्रश्न के अनुसार,

[(ka)b-c × (kb)c-a × (kc)a-b] × (x0 - 1)

= [(ka)b-c × (kb)c-a × (kc)a-b] × (1 - 1)

= [(ka)b-c × (kb)c-a × (kc)a-b] × 0

= 0

इस प्रकार, आवश्यक मान 0 है।

अत:, सही उत्तर विकल्प 3 है।

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