Question
Download Solution PDFयदि tan A = \(\frac{2}{3}\) है, तो sinA का मान ज्ञात कीजिए।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
tan A = \(\frac{2}{3}\)
प्रयुक्त सूत्र:
tan A = \(\frac{sin A}{cos A}\)
tan A = \(\frac{perpendicular}{Base}\)
sin A = \(\frac{Perpendicular}{Hypotenuse}\)
गणना:
जैसे tan A = \(\frac{sin A}{cos A}\) and tan A = \(\frac{perpendicular}{Base}\)
इस प्रकार, लंबवत = 2
आधार = 3
पाइथागोरस प्रमेय का प्रयोग करके,
H2 = P2 + B2
H2 = 22 + 32
H2 = 4 + 9
H2 = 13
H = \(\sqrt13\)
अब sin A = \(\frac{Perpendicular}{Hypotenuse}\)
sin A = \(\frac{2}{\sqrt13}\)
इसलिए, सही उत्तर '\(\frac{2}{\sqrt13}\)' है।
Last updated on Jul 7, 2025
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