Question
Download Solution PDFयदि एक बॉक्स में 4 लाल गेंदें और 6 नीली गेंदें हैं, तो एक ही रंग की 2 गेंदों को चुनने की प्रायिकता क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है
लाल गेंद = 4 और नीली गेंद = 6
सूत्र
P(E) = P(E1) + P(E2)
nCr = n!/r!(n – r)!
गणना
2 लाल गेंदों के निकाले जाने की प्रायिकता
⇒ P(E1) = 4C2/10C2
2 नीली गेंदों के निकाले जाने की प्रायिकता
P(E2) = 6C2/10C2
⇒ P(E) = = 4C2/10C2 + 6C2/10C2
⇒ (4C2 + 6C2)/10C2
⇒ [4!/2!(4 – 2)! + 6!/2!(6 – 2)!]/10!/2!(10 – 2)!
⇒ (6 + 15)/10!/2! × 8!
⇒ (21 × 2)/(10 × 9)
⇒ 42/90
⇒ P(E) = 7/15
∴ समान क्रम की 2 गेंदों को चुनने की प्रायिकता 7/15 है।Last updated on Jun 11, 2025
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