Question
Download Solution PDF\(\sqrt2\)x² - 2\(\sqrt5\)x + \(\sqrt3\) = 0 সমীকরণের বীজদ্বয়ের যোগফল হল-
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFঅনুসৃত ধারণা:
যদি একটি দ্বিঘাত সমীকরণ (ax² + bx + c = 0) হয়,
তাহলে, বীজদ্বয়ের যোগফল = -b/a
যেখানে b = x-এর সহগ
a = x²-এর সহগ
গণনা:
এখানে, আমাদের কাছে √2x² - 2√5x + √3 = 0 আছে।
এখন, সমীকরণটিকে √2 দিয়ে ভাগ করলে,
=> x² - √10x + √(3/2) = 0
এখন, এটি ax² + bx + c = 0 আকারে আছে।
যেখানে, a = 1, b = -√10, c = √(3/2)
আমরা জানি যে, বীজদ্বয়ের যোগফল = -b/a
=> -b/a = -(-√10) = √10
অতএব, বীজদ্বয়ের নির্ণেয় যোগফল √10
Last updated on Jul 11, 2025
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