Question
Download Solution PDFযদি sin θ = 2/√5 হয়, তাহলে sec2θ + cot2θ এর মান কত?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFপ্রদত্ত:
Sinθ = 2/√5
ধারণা:
ত্রিকোণমিতিক অপেক্ষকসমূহের ব্যবহার করে, sec θ এবং cot θ এর মান গণনা করুন।
গণনা:
sin θ = (লম্ব)/(অতিভুজ)
∆ABC এর;
(AC)2 = (AB)2 + (BC)2
⇒ (√5)2 = (2)2 + (BC)2
⇒ 5 = 4 + (BC)2
⇒ (BC)2 = 5 – 4
⇒ (BC)2 = 1
⇒ BC = 1
sec θ = (অতিভুজ)/ভূমি)
⇒ sec θ = √5/1 = √5
cot θ = (ভূমি)/(লম্ব)
⇒ cot θ = 1/2
(sec θ)2 + (cot θ)2 = (√5)2 + (1/2)2
⇒ 5 + 1/4
⇒ 21/4
∴ sec2θ + cot2θ এর মান হল 21/4
Last updated on Jun 13, 2025
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