Question
Download Solution PDFThe tangent to an ellipse x2 + 16y2 = 16 and making angle 60° with x-axis is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Straight Lines:
- The general equation of a line is y = mx + c, where m is the slope of the line.
- If the line y = mx + c makes an angle θ with the positive direction of the x-axis, then m = tan θ.
Tangents to an Ellipse:
- If the line y = mx + c touches the ellipse \(\rm \dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1\), then c2 = a2m2 + b2.
- The straight lines \(\rm y = mx \pm \sqrt{a^2m^2 + b^2}\) represent the tangents to the ellipse.
Calculation:
The given tangent makes an angle of 60∘ with the positive direction of the x-axis.
∴ m = tan 60∘ = √3.
Converting the given equation of the ellipse into the standard form \(\rm \dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1 \):
x2 + 16y2 = 16
⇒ \(\rm \dfrac{x^2}{4^2}+\dfrac{y^2}{1^2}=1 \)
∴ a = 4 and b = 1.
Using the formula \(\rm y = mx \pm \sqrt{a^2m^2 + b^2} \) for the tangents to the ellipse, the required equation is:
\(\rm y = \sqrt3x + \sqrt{4^2({\sqrt3})^2 + 1^2} \)
⇒ y = √3x + 7
⇒ √3x - y + 7 = 0.
Last updated on Jun 12, 2025
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