The base of a right prism is an equilateral triangle whose side is 10 cm. If height of this prism is 10\(\sqrt{3}\) cm, then what is the total surface area of prism ?

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SSC CGL Tier 2 Quant Previous Paper (Held On: 8 Aug 2022)
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  1. 125\(\sqrt{3}\) cm2
  2. 325\(\sqrt{3}\) cm2
  3. 150\(\sqrt{3}\) cm2
  4. 350\(\sqrt{3}\) cm2

Answer (Detailed Solution Below)

Option 4 : 350\(\sqrt{3}\) cm2
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Detailed Solution

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Given:

The base of a right prism is an equilateral triangle whose side is 10 cm.

The height of this prism is 10\(√{3}\) cm

Concept used:

TSA of Prism = [2(area of triangular base)] + [(Base Perimeter × height)]

Area of Equilateral Triangle = (√3/4)a2 

The perimeter of the Equilateral triangle = 3 × side.

Calculation:
F7 Vinanti SSC 06.07.23 D1
According to the concept,

⇒ Area of Equilateral Triangle = (√3/4)(10)2 = (100/4)√3 = 253

⇒ Base Perimeter = 10 × 3 = 30

Then,

TSA = [2(253)] + [30 × 10√3]

⇒ TSA = 50√3 + 3003

⇒ TSA = 350√3

∴ The total surface area of the prism is 3503.

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