Question
Download Solution PDFप्रवासाचा एक तृतीयांश भाग 25 किमी/ताशी या वेगाने कव्हर केला जातो, पुढचा एक तृतीयांश प्रवास 40 किमी/ताशी वेगाने कव्हर केला जातो आणि उर्वरित प्रवास 50 किमी/ताशी वेगाने पार केला जातो. संपूर्ण प्रवासासाठी सरासरी वेग (किमी/ताशी, 1 दशांश स्थानापर्यंत पूर्ण केला) किती आहे?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिले:
n = 3
S 1 = 25 किमी/ता
S 2 = 40 किमी/ता
S 3 = 5 0 किमी/ता
वापरलेले सूत्र:
जर अंतर 'n' समान भागांमध्ये विभागले गेले असेल तर प्रत्येकाने वेगवेगळ्या गतीने प्रवास केला असेल तर
सरासरी वेग = \(\frac{n}{\frac{1}{S_1}+\frac{1}{S_2}+\frac{1}{S_3}+. ...\frac{1}{S_n }}\)
कुठे, n = समान भागांची संख्या
गणना:
सरासरी वेग = \(\frac{3}{\frac{1}{25}+\frac{1}{40}+\frac{1}{50}}\)
⇒ सरासरी वेग = \(\frac{3}{\frac{8}{200}+\frac{5}{200}+\frac{4}{200}}\)
⇒ सरासरी वेग = ३ ÷ (१७/२००)
⇒ सरासरी वेग = (3 x 200)/17 = 35.29 ≈ 35.3 किमी/ता
∴ संपूर्ण प्रवासाचा सरासरी वेग 35.3 किमी/तास आहे.
Last updated on Jul 11, 2025
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