Question
Download Solution PDFजर S1 गोलाचे पृष्ठफळ हे S2 गोलाच्या पृष्ठफळापेक्षा 800% नी अधिक असेल आणि S2 चे घनफळ हे S1 पेक्षा x% नी कमी असेल, तर 'x' चे मूल्य टक्केवारीमध्ये (दोन दशांश स्थानापर्यंत) काढा:
Answer (Detailed Solution Below)
Detailed Solution
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प्रश्नानुसार,
⇒ S1 गोलाचे पृष्ठफळ : S2 गोलाचे पृष्ठफळ = 9 : 1
⇒ 4πR2 : 4πr2 = 9 : 1
⇒ R : r = 3 : 1
⇒ S1 चे घनफळ : S2 चे घनफळ = R3 : r3
⇒ S1 चा घनफळ : S2 चे घनफळ = 33 : 13
⇒ S1 चा घनफळ : S2 चे घनफळ = 27 : 1
S1 पेक्षा S2 चे घनफळ कमी असण्याची टक्केवारी = x%
x% = [(27 -1)/27] × 100 = (26/27) × 100 ≈ 96.29%
∴ पर्याय (3) योग्य आहे.
Last updated on Jul 8, 2025
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