Question
Download Solution PDF7.7 लिटर प्रति सेकंद या वेगाने पाईपद्वारे टाकी रिकामी केली गेली. जर टाकीची अंतर्गत त्रिज्या 10.5 मीटर असेल तर टाकीचा \(\frac{2}{3}\) भाग रिकामा करण्यासाठी किती वेळ (तासांमध्ये) लागेल?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
टाकीची अंतर्गत त्रिज्या 10.5 मीटर आहे
7.7 लिटर प्रति सेकंद या वेगाने पाईपद्वारे टाकी रिकामी केली गेली.
संकल्पना:
अर्धगोलाचे घनफळ = 2π/3 × r3
1 m3 = 1000 L
1000 cm3 = 1 L
गणना:
अर्धगोलीय टाकीचे घनफळ खालीलप्रमाणे आहे
⇒ 2/3 × 22/7 × 10.5 × 10.5 × 10.5
⇒ 2425.5 m3
टाकीची क्षमता खालीलप्रमाणे आहे
⇒ 2425.5 × 1000 L
⇒ 2425500 L
म्हणून,
टाकीचा 2/3 भाग रिकामा करण्यासाठी पाईपद्वारे लागणारा वेळ खालीलप्रमाणे आहे
⇒ (2/3 × 2425500) ÷ 7.7 सेकंद
⇒ 210,000 सेकंद
वेळ ही तासात दर्शविली आहे
⇒ 210,000/3600
⇒ 175/3 तास
∴ आवश्यक वेळ 175/3 तास आहे.
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