If P(A) = 2/3 and P(B) = 5/8 and find probability of only B occurring if probability of only A occurring is 1/6?

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SSC CGL Tier-II ( JSO ) 2017 Official Paper ( Held On : 22 Feb 2018 )
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  1. 1/8
  2. 1/9
  3. 1/6
  4. 2/9

Answer (Detailed Solution Below)

Option 1 : 1/8
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Detailed Solution

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Given

P(A) = 2/3

P(B) = 5/8

P(Only A occurring) = 1/6

Calculation

F1 Vishal Sirohi 28.5.21 Pallavi D2

P(A ∩ B) = P(A) – P(Only A occurring)

⇒ 2/3 – 1/6

P(A ∩ B) = ½

Probability of only B occurring = P(B) - P(A ∩ B)

⇒ 5/8 – 1/2

∴ Probability of only B occurring is 1/8
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