Question
Download Solution PDFयदि P(A) = 2/3 और P(B) = 5/8 है, तो केवल B के घटित होने की प्रायिकता ज्ञात कीजिए यदि केवल A के होने की प्रायिकता 1/6 है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है
P(A) = 2/3
P(B) = 5/8
P(केवल A के घटित होने की प्रायिकता) = 1/6
गणना
P(A ∩ B) = P(A) – P(केवल A के घटित होने की)
⇒ 2/3 – 1/6
P(A ∩ B) = ½
केवल B के घटित होने की प्रायिकता = P(B) - P(A ∩ B)
⇒ 5/8 – 1/2
∴ केवल B के घटित होने की प्रायिकता 1/8 है।Last updated on Jul 10, 2025
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