For a frequency distribution of a variable x, mean = 32, median = 30. The distribution is:

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SSC CGL Tier-II ( JSO ) 2016 Official Paper ( Held On : 2 Dec 2016 )
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  1. Positively skewed
  2. Negatively skewed
  3. Mesokurtic
  4. Platykurtic

Answer (Detailed Solution Below)

Option 1 : Positively skewed
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Detailed Solution

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Given

Mean = 32 

Median = 30

Formula

Mode = 3 × median - 2 × mean

Calculation

Mode = 3 × 30 - 2 × 32

∴ Mode = 26

Here Mode is least and median is lies between mean and mode

∴ Mean > Median > Mode

∴ This relation satisfied Positive skewed 

Key Points

Relation of mean, mode, and median for positive skewness is Mean > Median > Mode

Relation of mean, mode, and median for negative skewness is Mode > Median > Mean 

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