Rolle's theorem is a special case of

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  1. mean value theorem
  2. Leibnitz theorem
  3. Taylor series of a function
  4. Lagrange's theorem 

Answer (Detailed Solution Below)

Option 4 : Lagrange's theorem 

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Explanation:

रोल का प्रमेय

यदि f (x) एक फलन है जो निम्न को संतुष्ट करता है:

(i) f (x) बंद अंतराल [a, b] पर निरंतर है।

(ii) f (x) खुले अंतराल (a, b) पर अवकलनीय है। 

(iii) f (a) = f (b)

तो खुले अंतराल (a, b) में एक बिंदु c इस प्रकार मौजूद है जिससे f' (c) = 0 है।

Lagrange's Mean value theorem:

माना की f(x), [a, b] पर परिभाषित एक फलन है जैसे कि,

  1. f(x), [a, b] पर एक निरंतर है
  2. f(x), [a , b] पर अवकलनीय है

फिर, एक वास्तविक संख्या C ∈ (a, b) मौजूद होती है, जैसे कि, लाग्रेंज के माध्य मूल्य प्रमेय के अनुसार ,

f'(c) = \(\frac{{f\left( b \right) ~- ~f\left( a \right)}}{{b~ -~ a}}\)

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