निम्नलिखित निश्चित समाकलन का मान निकालें और सही उत्तर चुनियें:

\(\int_1^2\) x . dx

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Bihar STET Paper I: Mathematics (Held In 2019 - Shift 1)
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  1. \(\frac{3}{2}\)
  2. \(\frac{2}{3}\)
  3. \(\frac{3}{5}\)
  4. \(\frac{2}{5}\)

Answer (Detailed Solution Below)

Option 1 : \(\frac{3}{2}\)
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Bihar STET Paper 1 Mathematics Full Test 1
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Detailed Solution

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प्रयुक्त अवधारणा:

 

\(\int_a^b\) xn.dx = (xn+1/n+1)ab

गणना:

\(\int_1^2\) x . dx = x1+1/1+1 = (x2/2)12 = 4/2 - 1/2 = 2 - 1/2 = 3/2.

अतः, विकल्प 1 सही है।

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