एक चर x के बारंबारता बंटन के लिए माध्य = 32, माध्यिका = 30 हैं। बंटन                        है। 

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SSC CGL Tier-II ( JSO ) 2016 Official Paper ( Held On : 2 Dec 2016 )
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  1. धनात्मक विषम
  2. ऋणात्मक विषम
  3. मेसोकुर्टिक
  4. प्लेटिकुर्टिक

Answer (Detailed Solution Below)

Option 1 : धनात्मक विषम
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PYST 1: SSC CGL - English (Held On : 11 April 2022 Shift 1)
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Detailed Solution

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दिया गया है

माध्य = 32 

माध्यिका = 30

सूत्र 

बहुलक = 3 × माध्यिका - 2 × माध्य 

गणना

बहुलक = 3 × 30 - 2 × 32

∴ बहुलक = 26

यहाँ बहुलक सबसे छोटा है और माध्यिका माध्य और बहुलक के बीच स्थित है। 

∴ माध्य > माध्यिका > बहुलक 

∴ यह संबंध धनात्मक विषम को संतुष्ट करता है। 

Key Points

धनात्मक विषमता के लिए माध्य, बहुलक और माध्यिका का संबंध माध्य > मध्यिका > बहुलक है। 

ऋणात्मक विषमता के लिए माध्य, बहुलक और माध्यिका का संबंध बहुलक > मध्यिका > माध्य है। 

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