sin-1 (cos x), x∈ [-π/2, π/2] का मान ज्ञात कीजिए।

Question

Question

Answer 1

संकल्पना:

sin-1 (sin x) = x

गणना:

दिया गया है: x∈ [-π/2, π/2]

sin-1 (cos x) = sin-1 sin \(\rm \left(\frac {\pi}{2} - x\right)\)

चूँकि हम जानते हैं कि, sin-1 (sin x) = x

अतः sin-1 (cos x) = sin-1 sin \(\rm \left(\frac {\pi}{2} - x\right)\) = \(\rm \left(\frac {\pi}{2} - x\right)\)