Question
Download Solution PDFA resistor of 8 Ω and a capacitor of 178 μF are connected in series to a 250V, 50 Hz supply. Net impedance of the circuit is given by 19.6 Ω. What is the value of reactive power?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The reactive power is given by:
Q = (I)2 Xc
The current in a circuit is given by:
\(I={V_s \over Z}\)
where, Q = Reactive power
V = Voltage
I = Current
Z = Net impedance
Xc = Capacitive Reactance
Calculation
Given, Vs = 250 V
Z = 19.6 Ω
\(I={250 \over 19.6}=12.755\space A\)
\(X_C={1\over 2\pi fC}\)
\(X_C={1\over 2\pi × 50× 178× 10^{-6} }=17.891\space \Omega\)
Q = (12.755)2 × 17.891
Q = 2912.5 VAR
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