Question
Download Solution PDFA can do a piece of work in 5 days. B can do it in 20 days. With the assistance of C, they completed the work in 2 days. C alone can do it in ______________days.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
A can complete the work in 5 days.
B can complete the work in 20 days.
With the assistance of C, they complete the work in 2 days.
Formula used:
Work done per day = Efficiency
Calculation:
LCM of (5, 20, 2) = 20 (Total work units)
Efficiency of A = \( \frac{20}{5} = 4 \) units/day
Efficiency of B = \( \frac{20}{20} = 1 \) unit/day
Efficiency of (A + B + C) = \( \frac{20}{2} = 10 \) units/day
⇒ 4 + 1 + C = 10
⇒ C = 10 - 5
⇒ C = 5 units/day
Time taken by C alone = \( \frac{20}{5} = 4 \) days
∴ C alone can complete the work in 4 days.
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