Question
Download Solution PDFA, B and C can do a piece of work in 15, 10 and 30 days, respectively. In how many days can A do the work if he is assisted by B and C on every 3rd day?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Time taken by A = 15 days
Time taken by B = 10 days
Time taken by C = 30 days
B and C both assist A on every third day
Formula used:
Work = Efficiency × Time
Calculation:
LCM of 15, 10, and 30 is 30
Efficiency of A = 30/15 = 2 units/day
Efficiency of B = 30/10 = 3 units/day
Efficiency of C = 30/30 = 1 unit/day
Work done by A on the first two days = (2 × 2) = 4 units
Work done by A, B, and C together on the third day = (2 + 3 + 1) = 6 units
Total work done by A, B, and C in 3 days = (4 + 6) = 10 units
Similarly, work done by A, B, and C in the next three days = 10 units
Total work done by A, B, and C in 6 days = (10 + 10) = 20 units
Remaining work = 30 - 20 = 10 units
Total work done by A, B, and C in naxt days = 10 units
Number of days taken by A to complete the remaining work = 3 + 3 + 3 = 9 days
∴ The required time is 9 days.
Last updated on Jun 16, 2025
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