Design of Steel Structures MCQ Quiz in বাংলা - Objective Question with Answer for Design of Steel Structures - বিনামূল্যে ডাউনলোড করুন [PDF]
Last updated on Mar 8, 2025
Latest Design of Steel Structures MCQ Objective Questions
Top Design of Steel Structures MCQ Objective Questions
Design of Steel Structures Question 1:
Horizontal web stiffener are used in plate girders if depth to thickness ratio of web is greater than
Answer (Detailed Solution Below)
Design of Steel Structures Question 1 Detailed Solution
Concepts:
As per IS 800:2007:
If
d/tw < 67ϵ ; no stiffener is required
85ϵ < d/tw < 200ϵ ; vertical intermediate stiffeners are provided
d/tw > 200; Horizontal stiffeners are provided.
In all above cases; d is the depth of web and tw is thickness of web.
Note:
The different type of stiffeners and their function is given below in tabulated form:
Stiffener |
Function |
Bearing stiffener |
To prevent Web Crushing at the location of heavy concentrated loads. |
Tension Stiffener |
To transfer tensile forces from flange to web |
Load Carrying Stiffener |
To prevent Web buckling due to any concentrated load. |
Torsional Stiffener |
To restrain girder against torsional effects at supports. |
Diagonal Stiffener |
Strengthen of web under the combination of bending and shear |
Horizontal Stiffener |
To prevent Web buckling against compressive force due to bending |
Design of Steel Structures Question 2:
As per ‘Indian Standard General Construction in Steel- Code of practice’ for deep penetration welds, where the depth of penetration beyond the root run is a minimum of 2.4 mm, the size of fillet should be as:
Answer (Detailed Solution Below)
Design of Steel Structures Question 2 Detailed Solution
Explanation:
As per IS 800: 2007 -
- The size of normal fillets shall be taken as the minimum weld leg size.
- For deep penetration welds, where the depth of penetration beyond the root run is a minimum of 2.4 mm, the size of the fillet should be taken as the minimum leg size plus 2.4 mm.
- For fillet welds made by semi-automatic or automatic processes, where the depth of penetration is considerably in excess of 2.4 mm, the size shall be taken considering the actual depth of penetration.
- The size of fillet welds shall not be less than 3 mm.\
- The minimum size of the weld is based on the thickness of the thicker plate being connected as shown in the below-tabulated form:
Thickness of thicker plate connected (mm) |
≤ 10 mm |
11-20 mm |
21-32 mm |
> 32 mm |
Minimum size of the weld (mm) |
3 mm |
5 mm |
6 mm |
8 mm |
Design of Steel Structures Question 3:
In case of welds using lap joints, the minimum lap should not be less than four times the thickness of the thinner part joined or t mm, whichever is more, where t (mm) is:
Answer (Detailed Solution Below)
Design of Steel Structures Question 3 Detailed Solution
Concept:
(i) For the size of the weld:
Minimum size of weld:
t (mm) |
0 - 10 |
11-20 |
21-32 |
32-50 |
Smin(mm) |
3 |
5 |
6 |
8 |
The minimum size of the weld is required to avoid stress concentration in welds.
Maximum size of weld:
Smax = t - 1.5 mm for pointed edge
\(= \frac{{3{\rm{t}}}}{4}\) for rounded edge
Where t is the thickness of the thicker member
The size of welded is limited to ensure uniform stress distribution.
(ii) Length of weld/lap of length
Lp min = 4t or 40 mm (as per WSM)
= 5t or 50 mm (as per LSM)
Design of Steel Structures Question 4:
As per IS 800 : 2007, the value of imperfection factor for buckling class "b" is
Answer (Detailed Solution Below)
Design of Steel Structures Question 4 Detailed Solution
Concept:
Imperfection Factor: It takes into account, the imperfection that may occur while load transferring, fabrication, or installation.
It depends upon the shape of the column cross-section under consideration, the direction in which buckling can occur, and the fabrication process (hot rolled, welded or cold-formed).
Classification of different sections under different buckling class i.e. a, b, c or d used for the design of axial compression member.
As per IS 800: 2007, Table 7;
Buckling Class |
a |
b |
c |
d |
α |
0.21 |
0.34 |
0.49 |
0.76 |
∴ The imperfection factor for buckling class b is 0.34
Design of Steel Structures Question 5:
The permissible maximum deflection of a purlin of 4.5 m which is subjected to live load supporting GI metal sheet and supported by elastic cladding is:
Answer (Detailed Solution Below)
Design of Steel Structures Question 5 Detailed Solution
Vertical Deflection limits for industrial buildings as per IS 800:2007 are:
a) For Purlins and Girts subjected to live load/wind load supported on elastic cladding, maximum deflection is limited to span / 150.
b) For Purlins and Girts subjected to live load/wind load supported on Brittle cladding, maximum deflection is limited to span / 180.
Calculation:
∴ Permissible maximum deflection = Span/150 = 4500/150 = 30 mm
Design of Steel Structures Question 6:
Calculate the effective length of column having c/c length of 4m and both ends are fixed as per IS 800-2007.
Answer (Detailed Solution Below)
Design of Steel Structures Question 6 Detailed Solution
Explanation:
As per IS: 800 - 2007
The design value of the effective length factor for various combinations is given below:
Given both ends are fixed
So the Case becomes Restrained in all movements
So effective length = 0.65 × L = 0.65 × 4 = 2.6 m
Design of Steel Structures Question 7:
When gantry girders carry moving loads such as charging cars, the deflection should not exceed
Answer (Detailed Solution Below)
Design of Steel Structures Question 7 Detailed Solution
Explanation:
AS per IS 800(2007) (C- 5.6.1 Dejection)
Types of Gantry Girder |
Permissible Deflection |
When cranes are manually operated |
L/500 |
When cranes are travelling overhead and operated electrically up to 500 KN |
L/750 |
When cranes are travelling overhead and operated electrically over 500 KN |
L/1000 |
Other moving loads such as charging cars etc. |
L/600 |
Design of Steel Structures Question 8:
The shape factor for circular section is ______.
Answer (Detailed Solution Below)
Design of Steel Structures Question 8 Detailed Solution
Explanation:
Shape factor:
The shape factor is defined as the ratio of the fully plastic moment to yield moment of section. Shape factor depend upon cross-section.
Some standard shape factors are as follows:
Triangular | 2.34 |
Rectangular | 1.5 |
Circular | 1.7 |
Diamond | 2 |
Hollow Circular | 1.27 |
Design of Steel Structures Question 9:
The permissible bending stress in the slab base of steel columns for all grades of steel is limited to
Answer (Detailed Solution Below)
Design of Steel Structures Question 9 Detailed Solution
Permissible stresses in steel structure members:
S.No. |
Types of stress |
Permissible stress (MPa) |
Factor of safety |
1 |
Axial Tensile stress |
0.6 fy |
1.67 |
2 |
Maximum axial compressive stress |
0.6 fy |
1.67 |
3 |
Bending tensile stress |
0.66 fy |
1.515 |
4 |
Maximum bending compressive stress |
0.66 fy |
1.515 |
5 |
Average shear stress |
0.4 fy |
2.5 |
6 |
Maximum shear stress |
0.45 fy |
2.22 |
7 |
Bearing stress |
0.75 fy |
1.33 |
8 |
Stress in slab base |
185 |
- |
∴ The permissible bending stress in the slab base of steel columns for all grades of steel is limited to 185.
Design of Steel Structures Question 10:
As per IS : 800 - 2007, the partial safety factor for materials, in which resistance is governed by the ultimate stress, is ______.
Answer (Detailed Solution Below)
Design of Steel Structures Question 10 Detailed Solution
Explanation:
As per IS 800:2007, Table 5, Partial safety factors for materials are given as:
(i) When resistance is governed by ultimate stress, γm1 = 1.25
(ii) When resistance is governed by yielding, γmo = 1.1
(iii) Resistance of member to buckling,γmo = 1.1
(iv) Resistance of connection:
- Bolts-Friction Type or Rivets = 1.25
- Welds = 1.25 (shop fabrications) and 1.5 (Field fabrications)