Question
Download Solution PDFWhat is the number of digits required for numbering a book with 428 pages?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Total number of pages = 428
Formula Used:
Total digits required = (Number of pages with 1 digit) + (Number of pages with 2 digits × 2) + (Number of pages with 3 digits × 3)
Calculation:
Pages with 1 digit: 1 to 9
Number of pages = 9
Digits required = 9
Pages with 2 digits: 10 to 99
Number of pages = 99 - 10 + 1
Number of pages = 90
Digits required = 90 × 2
Digits required = 180
Pages with 3 digits: 100 to 428
Number of pages = 428 - 100 + 1
Number of pages = 329
Digits required = 329 × 3
Digits required = 987
Total digits required = 9 + 180 + 987
⇒ Total digits required = 1176
The total number of digits required for numbering a book with 428 pages is 1176.
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