The Output of NAND Gate is low in case 

This question was previously asked in
RRB ALP Instrument Mechanic 23 Jan 2019 Official Paper (Shift 1)
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  1. any one of the inputs is LOW
  2. any one of the inputs is HIGH
  3. all of the inputs are HIGH
  4. all of the inputs are LOW

Answer (Detailed Solution Below)

Option 3 : all of the inputs are HIGH
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Detailed Solution

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The correct option is 3

Concept:

NAND GATE

Symbol:

F1 U.B Madhu 15.11.19 D 16

Truth Table:

Input A

Input B

Output

\(Y = \overline {AB}\)

0

0

1

0

1

1

1

0

1

1

1

0

 

Output Equation: \(Y = \overline {A.B} = \overline A + \overline B\)

Key Points:

1) If A is always High, the output is the inverted value of the other input B, i.e. B̅

2) The output is low only when both the inputs are high

3) It is a universal gate

26 June 1

A

B

EXOR

EXNOR

NAND

NOR

0

0

0

1

1

1

0

1

1

0

1

0

1

0

1

0

1

0

1

1

0

1

0

0

 

From the truth table when A = B = 0,Output Y = 1 for NAND and NOR gate

Also when A = B = 1, output Y = 0 for NAND and NOR gate

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