The following is the table containing data recorded during curve setting by using the two theodolite method.

Point

Chord Length

Tangential Angle

Deflection Angle

Theodolite reading at

Point of Curve

Point of Tangency

P1

12.26 m

0° 21' 25"

A

   

P2

20 m

1° 12' 5"

 

B

 

P3

20 m

1° 12' 5"

   

C

P4

20 m

1° 12' 5"

3° 57' 40"

   


The values of A, B and C are ____, ____ and ____, respectively.

This question was previously asked in
SSC JE Civil 9 Oct 2023 Shift 1 Official Paper-I
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  1. A = 0° 21’ 25”; B = 1° 54’ 55”; C = 177° 14’ 25”
  2. A = 0° 21’ 25”; B = 1° 33’ 30”; C = 357° 14’ 25”
  3. A = 0° 21’ 25”; B = 1° 33’ 30”; C = 177° 14’ 25”
  4. A = 0° 21’ 25”; B = 1° 33’ 30”; C = 182° 45’ 35”

Answer (Detailed Solution Below)

Option 2 : A = 0° 21’ 25”; B = 1° 33’ 30”; C = 357° 14’ 25”
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Detailed Solution

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Concept:

F1 Savita ENG 11-12-23 D5F1 Savita ENG 11-12-23 D6

Two Theodolite Method

  • In this method, two theodolites are used for the angular measurements and no linear measurements are taken.
  • One theodolite is set at the point of curvature (T1) and the other at the point of tangency (T2).
  • This method is quite accurate.
  • This method is convenient, specially when the ground is rough, and accurate chaining is not possible.

Calculation:

 

Point

Chord Length

Tangential Angle

Deflection Angle

Theodolite reading at

Point of Curve

Point of Tangency

P1

12.26 m

0° 21' 25"

A

   

P2

20 m

1° 12' 5"

 

B

 

P3

20 m

1° 12' 5"

   

C

P4

20 m

1° 12' 5"

3° 57' 40"

   

Calculation are based on the above figure

For calculation of A, it will be equal to tangential deflection angle.

A = 0° 21' 25"

For calculation of B (point of curve), it will be sum of tangential angle up to that point.

B = 0° 21' 25" + 1° 12' 5" = 1° 33’ 30”

For calculation of C (point of tangency), it will be the difference of 360° with sum of tangential angle up to point C

C = 360° - (0° 21' 25"+1° 12' 5"+1° 12' 5") =  357° 14’ 25”

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