Question
Download Solution PDFఒక అర్ధగోళం యొక్క వ్యాసార్థం 14 సెం.మీ. దాని వక్ర ఉపరితల వైశాల్యం (సెం.మీ2లో) ఎంత ఉంటుంది? (π = 22/7 ఉపయోగించండి)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFఇచ్చింది:
ఒక అర్ధగోళం వ్యాసార్థం = 14 సెం.మీ.
భావన:
ఒక అర్ధగోళం యొక్క వక్ర ఉపరితల వైశాల్యం = 2πr2
సాధన:
⇒ వక్ర ఉపరితల వైశాల్యం = 2 × (22/7) × 142 = 1232 సెం.మీ2
అందువల్ల, అర్ధగోళం యొక్క వక్ర ఉపరితల వైశాల్యం 1232 సెం.మీ2.
Last updated on Jun 11, 2025
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