Question
Download Solution PDFఒక అర్ధగోళం యొక్క వ్యాసార్థం 14 సెం.మీ. దాని వక్ర ఉపరితల వైశాల్యం (సెం.మీ2లో) ఎంత ఉంటుంది? (π = 22/7 ఉపయోగించండి)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFఇచ్చింది:
ఒక అర్ధగోళం వ్యాసార్థం = 14 సెం.మీ.
భావన:
ఒక అర్ధగోళం యొక్క వక్ర ఉపరితల వైశాల్యం = 2πr2
సాధన:
⇒ వక్ర ఉపరితల వైశాల్యం = 2 × (22/7) × 142 = 1232 సెం.మీ2
అందువల్ల, అర్ధగోళం యొక్క వక్ర ఉపరితల వైశాల్యం 1232 సెం.మీ2.
Last updated on Jun 12, 2025
-> The SSC GD Notification 2026 will be released in October 2025 and the exam will be scheduled in the month of January and February 2026.
-> The SSC GD Merit List is expected to be released soon by the end of April 2025.
-> Previously SSC GD Vacancy was increased for Constable(GD) in CAPFs, SSF, Rifleman (GD) in Assam Rifles and Sepoy in NCB Examination, 2025.
-> Now the total number of vacancy is 53,690. Previously, SSC GD 2025 Notification was released for 39481 Vacancies.
-> The SSC GD Constable written exam was held on 4th, 5th, 6th, 7th, 10th, 11th, 12th, 13th, 17th, 18th, 19th, 20th, 21st and 25th February 2025.
-> The selection process includes CBT, PET/PST, Medical Examination, and Document Verification.
-> The candidates who will be appearing for the 2025 cycle in the exam must attempt the SSC GD Constable Previous Year Papers. Also, attempt SSC GD Constable Mock Tests.