Question
Download Solution PDFరామ్ 50 W మరియు 220 V రేటింగ్ ఉన్న బల్బును కొనుగోలు చేశాడు. ఇది 220 V సప్లైకి కనెక్ట్ చేయబడినప్పుడు, దాని నిరోధం ఇలా ఉంటుంది:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFసరైన సమాధానం ఆప్షన్ 2)968 Ω
ఇవ్వబడినవి:
\(P=50W,V=220V\)
సూత్ర౦:
\(P={V^2\over R}\)
లెక్కింపు:
\(P={V^2\over R}\)
\(R={V^2\over P}\)
\(R={220^2\over 50}\)
\(R={48400\over 50}=968Ω\)
అందువలన, బల్బు యొక్క నిరోధం 968 Ω.
Last updated on Jun 30, 2025
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