Question
Download Solution PDFറാം 50 W, 220 V എന്നിങ്ങനെ നിരക്കുകൾ ഉള്ള ഒരു ബൾബ് വാങ്ങി. അത് 220 V സപ്ലൈയുമായി ബന്ധിപ്പിക്കുമ്പോൾ, അതിന്റെ പ്രതിരോധം ഇതായിരിക്കും:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFശരിയായ ഉത്തരം ഓപ്ഷൻ 2)968 Ω ആണ്
നൽകിയത്:
\(P=50W,V=220V\)
സൂത്രവാക്യം:
\(P={V^2\over R}\)
കണക്കുകൂട്ടൽ:
\(P={V^2\over R}\)
\(R={V^2\over P}\)
\(R={220^2\over 50}\)
\(R={48400\over 50}=968Ω\)
അതിനാൽ, ബൾബിന്റെ പ്രതിരോധമാണ് 968 Ω.
Last updated on Jun 30, 2025
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