Question
Download Solution PDFSohan makes four trips of equal distances. His speed on first trip was 240 km/hr and in each subsequent trip his speed was half of the previous trip. What is the average speed of Sohan in these four trips?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven Data:
Speeds: 240, 120, 60, 30 km/hr
Concept:
Time taken for each trip:
1st trip: Time = d/240 hr
2nd trip: Time = d/120 hr
3rd trip: Time = d/60 hr
4th trip: Time = d/30 hr
Total distance for 4 trips = 4d
Total time taken for 4 trips = d/240 + d/120 + d/60 + d/30
1st trip: d/240
2nd trip: 2d/240
3rd trip: 4d/240
4th trip: 8d/240
Total time taken = (d + 2d + 4d + 8d) / 240 = 15d/240 = d/16
Average Speed = Total Distance/Total Time = 4d / (d/16) = 4d × 16/d = 64 km/hr
So, the average speed of Sohan for these four trips is 64 km/hr.
Therefore, the average speed of Sohan in these four trips is 64 km/hr
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