Question
Download Solution PDFज्याचे शिरोबिंदू निर्देशांक (1, 2), (-4, -3) आणि (4, 1) द्वारे दिले आहेत. अशा त्रिकोणाचे क्षेत्रफळ किती?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFवापरलेले सूत्र:
ज्याचे शिरोबिंदू (x1, y1), (x2, y2) and (x3, y3) आहेत, त्या त्रिकोणाचे क्षेत्रफळ = ½ [x1 (y2 - y3) + x2 (y3 - y1) + x3 (y1 - y2)]
गणना :
⇒ त्रिकोणाचे क्षेत्रफळ = (1/2) × [1(-3 – 1) + (-4) (1 – 2) + 4{2 – (-3)}] = (1/2) × {(-4) + 4 + 20} = 20/2 = 10 चौ. एकक
Last updated on Jun 2, 2025
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