Question
Download Solution PDF34 सेमी कर्ण असणाऱ्या एका आयताकृती शेताची लांबी त्याच्या रुंदीपेक्षा 14 सेमी जास्त आहे, त्या शेताची परिमिती शोधा.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
एका आयताकृती शेताची लांबी त्याच्या रुंदीपेक्षा 14 सेमी जास्त आहे
त्याच्या कर्णाची लांबी = 34 सेमी
संकल्पना:
महत्त्वमापन
सूत्र वापरले:
आयताची परिमिती = 2(l + b)
गणना:
त्या शेताची लांबी आणि रुंदी अनुक्रमे 'x + 14' आणि 'x' मानू
कर्ण = 34 = \(\sqrt {{{\left( {x + 14} \right)}^2} + {x^2}} \)
⇒ 1156 = x2 + 196 + 28x + x2
⇒ x2 + 14x – 480 = 0
⇒ x2 + 30x - 16x - 480 = 0
⇒ x(x + 30) - 16(x + 30) = 0
⇒ (x + 30) (x - 16) = 0
⇒ x = 16
तर,
शेताची परिमिती = 2 [(x + 14) + x]
= 2 × 46
= 92 सेमी
∴ शेताची परिमिती 92 सेमी आहे.
Last updated on Jun 13, 2025
-> The SSC CGL Notification 2025 has been released on 9th June 2025 on the official website at ssc.gov.in.
-> The SSC CGL exam registration process is now open and will continue till 4th July 2025, so candidates must fill out the SSC CGL Application Form 2025 before the deadline.
-> This year, the Staff Selection Commission (SSC) has announced approximately 14,582 vacancies for various Group B and C posts across government departments.
-> The SSC CGL Tier 1 exam is scheduled to take place from 13th to 30th August 2025.
-> Aspirants should visit ssc.gov.in 2025 regularly for updates and ensure timely submission of the CGL exam form.
-> Candidates can refer to the CGL syllabus for a better understanding of the exam structure and pattern.
-> The CGL Eligibility is a bachelor’s degree in any discipline.
-> Candidates selected through the SSC CGL exam will receive an attractive salary. Learn more about the SSC CGL Salary Structure.
-> Attempt SSC CGL Free English Mock Test and SSC CGL Current Affairs Mock Test.
-> Candidates should also use the SSC CGL previous year papers for a good revision.