Question
Download Solution PDF9 सेमी त्रिज्या असलेले एक गोलाकार एक खरबूज दोन समान गोलार्धांमध्ये कापले जाते. तर प्रत्येक निम्म्या भागाचे घनफळ (सेमी3मध्ये, 2 दशांश स्रथानांपर्यंत योग्य) शोधा. \(\pi = {22 \over7}\) घ्या.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेली माहिती:
गोलाची त्रिज्या (r) = 9 सेमी
वापरलेले सूत्र:
गोलाचे घनफळ = 4/3 × π × r3
उत्तर:
⇒ गोलाचे घनफळ = 4/3 × 22/7 × (9 सेमी)3
⇒ गोलाचे घनफळ = 3054.85 सेमी3
गोल दोन समान गोलार्धांमध्ये कापला असल्याने, प्रत्येक अर्ध्या भागाचा आकार गोलाच्या अर्ध्या भागाचा असतो.
⇒ प्रत्येक अर्ध्या भागाचे घनफळ = 3054.85 सेमी3/2 = 1527.43 सेमी3
म्हणून, प्रत्येक अर्ध्या भागाचे घनफळ अंदाजे 1527.43 सेमी3 आहे.
Last updated on Jun 30, 2025
-> The Staff Selection Commission has released the SSC GD 2025 Answer Key on 26th June 2025 on the official website.
-> The SSC GD Notification 2026 will be released in October 2025 and the exam will be scheduled in the month of January and February 2026.
-> The SSC GD Merit List is expected to be released soon by the end of April 2025.
-> Previously SSC GD Vacancy was increased for Constable(GD) in CAPFs, SSF, Rifleman (GD) in Assam Rifles and Sepoy in NCB Examination, 2025.
-> Now the total number of vacancy is 53,690. Previously, SSC GD 2025 Notification was released for 39481 Vacancies.
-> The SSC GD Constable written exam was held on 4th, 5th, 6th, 7th, 10th, 11th, 12th, 13th, 17th, 18th, 19th, 20th, 21st and 25th February 2025.
-> The selection process includes CBT, PET/PST, Medical Examination, and Document Verification.
-> The candidates who will be appearing for the 2026 cycle in the exam must attempt the SSC GD Constable Previous Year Papers. Also, attempt SSC GD Constable Mock Tests.