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2.5 കി.ഗ്രാം പിണ്ഡമുള്ള ഒരു ഉരുക്ക് പാത്രത്തിന്റെ താപനില 10 ഡിഗ്രി കൂടിയാൽ അതിന്റെ താപ ശേഷി കണ്ടെത്തുക. ഉരുക്കിന്റെ പ്രത്യേക താപ ശേഷി 500 Jkg-1K-1 ആണ്.

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  1. 200 Jkg-1K-1
  2. 1,250 JK-1
  3. 125 JK-1
  4. 20 Jkg-1K-1

Answer (Detailed Solution Below)

Option 2 : 1,250 JK-1
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Detailed Solution

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ആശയം:

താപ ഊർജ്ജം നേടിയത് അല്ലെങ്കിൽ നഷ്ടപ്പെട്ടത്:

  • വസ്തുവിന് ലഭിക്കുന്ന താപ ഊർജ്ജം അതിന്റെ പിണ്ഡം, സ്വഭാവം, താപനിലയിലെ മാറ്റം എന്നിവയെ ആശ്രയിച്ചിരിക്കുന്നു.
  • ഗണിതശാസ്ത്രപരമായി, ഇത് ഇങ്ങനെ പ്രതിനിധീകരിക്കാൻ കഴിയും:

Q = m × c × ΔT

Q = താപ നേട്ടം , m = പിണ്ഡം, c = പ്രത്യേക താപം, ΔT = താപനിലയിലെ മാറ്റം

താപ ശേഷി:

  • ഹീറ്റ് കപ്പാസിറ്റി അല്ലെങ്കിൽ താപ ശേഷി എന്നത് ദ്രവ്യത്തിന്റെ ഒരു ഭൗതിക സ്വഭാവമാണ്, ഒരു വസ്തുവിന് അതിന്റെ താപനിലയിൽ ഒരു യൂണിറ്റ് മാറ്റം ഉണ്ടാക്കുന്നതിനായി നൽകേണ്ട താപത്തിന്റെ അളവ് നിർവചിക്കപ്പെടുന്നു.
  • താപ ശേഷിയുടെ SI യൂണിറ്റ് ജൂൾ പെർ കെൽവിനാണ് (J/K).

കണക്കുകൂട്ടൽ:

നൽകിയിരിക്കുന്നത്:

പിണ്ഡം, m = 2.5 kg, ΔT = 10°C, പ്രത്യേക താപ ശേഷി, c = 500 Jkg-1K-1

താപ ശേഷി​ = m × c = 2.5 × 500 = 1,250 JK-1

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