In two identical tubes A and B, tube A has both ends open, while tube B has one end closed. The ratio of fundamental frequency of tubes A and B is (A : B) -

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  1. 1 : 2 
  2. 1 : 4 
  3. 2 : 1 
  4. 4 : 1

Answer (Detailed Solution Below)

Option 3 : 2 : 1 
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Detailed Solution

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Formula Used:

  • Frequency of sound in open pipe = \(\frac{v}{2l}\)
  • Frequency of sound in close pipe = \(\frac{v}{4l}\)
  • If the frequency of open pipe is A and close pipe is B.
     

In that case,

A : B = \(\frac{v}{2l}\) \(\frac{v}{4l}\) = 2 : 1

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