In the given figure, the circle with centre O has radius 10 cm. The radius of the circle with centre P is x. STR is a common tangent to the two circles at points R and S as shown in the figure. RT = 16 cm and TS = 24 cm. What is the value of x (in cm)?

F5 Savita SSC 16-12-22 D2

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  1. 15
  2. 16
  3. 12
  4. 18

Answer (Detailed Solution Below)

Option 1 : 15
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SSC CPO : English Comprehension Sectional Test 1
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Detailed Solution

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Given:

The circle with center O has a radius of 10 cm

STR is a common tangent to the two circles at points R and S

RT = 16 cm

TS = 24 cm

Concept Used:

When two lines intersect each other the opposite angles are always equal

Calculations:

F5 Savita SSC 16-12-22 D2

As we can see, Line RS and Line OP intersect each other 

⇒ therefore, \(\angle\) RTO = ​​\(\angle\) STP

Let \(\angle \) RTO be y

In \(\triangle\)ROT

⇒ tan y = \(\frac{RO}{RT}=\frac{10}{16}\)

similarly,

In \(\triangle\)STP

⇒ tan y = \(\frac{SP}{ST}=\frac{x}{24}\)

As both the angle are equal, so we get

⇒ \(\frac{10}{16}=\frac{x}{24}\)

⇒ x = \(\frac{10\times24}{16}\) = 15 cm

⇒ Hence, The radius of the circle of center P is 15 cm.

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