Question
Download Solution PDFदिए गए चित्र में, O वृत्त का केंद्र है तो OP||QR है, QR वृत्त की स्पर्श-रेखा है और OP = 6 सेमी है, ∆OPR का क्षेत्रफल ज्ञात कीजिये।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFOP||QR (दिया है)
⇒ बिंदु P को बिंदु S तक इस प्रकार बढ़ाते हैं कि QR = OS
अतः आयत QRSO का निर्माण होता है
⇒ OQ = SR = 6 सेमी (∆OPR की ऊंचाई)
⇒ OP = 6 सेमी = ∆OPR का आधार
⇒ ∆OPR का क्षेत्रफल = 1/2 × 6 × 6 = 18 सेमी2
Last updated on Jul 17, 2025
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