Question
Download Solution PDF100 W वाहक शक्ति वाले 100% मॉडुलित AM सिग्नल में, निचले साइडबैंड में शक्ति क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFअवधारणा:
एक AM प्रणाली के लिए कुल संचरित शक्ति इस प्रकार दी गई है:
\({P_t} = {P_c}\left( {1 + \frac{{{μ^2}}}{2}} \right)\)
Pc = वाहक शक्ति
μ = मॉडुलन सूचकांक
उपरोक्त व्यंजक को इस प्रकार विस्तारित किया जा सकता है:
\({P_t} = {P_c} + P_c\frac{{{μ^2}}}{2}\)
कुल शक्ति वाहक शक्ति और साइडबैंड शक्ति का योग है, अर्थात्
\({P_s} = P_c\frac{{{μ^2}}}{2}\)
गणना:
दिया गया: Pc = 100 W और μ = 1
हम लिख सकते हैं:
\({P_s} = P_c\frac{{{μ^2}}}{2}\)
\(= 100 \times \frac{1^2}{2}\)
\(P_s=50~W\)
कुल साइडबैंड शक्ति = 50 W
ऊपरी साइडबैंड में शक्ति + निचले साइडबैंड में शक्ति = 50 W
ऊपरी साइडबैंड में शक्ति = निचले साइडबैंड में शक्ति = 25 W
Last updated on Jun 7, 2025
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