Question
Download Solution PDFयदि \(\Delta ABC \cong \Delta PQR\), BC = 6 सेमी, और \(\angle A = {75^o}\) है, तो निम्न में से कौन-सा सत्य है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
\(\Delta ABC \cong \Delta PQR\)
BC = 6 सेमी
\(\angle A = {75^o}\)
प्रयुक्त अवधारणा:
दो त्रिभुजों को सर्वांगसम कहा जाता है यदि तीनों संगत भुजाएँ समान होती हैं और तीनों संगत कोण माप में समान होते हैं।
गणना:
यदि त्रिभुज ABC और PQR सर्वांगसम हैं, तो
∠A = ∠Q और ∠B = ∠R
Δ PQR की भुजा QR, Δ ABC की भुजा BC के बराबर होनी चाहिए ताकि दोनों त्रिभुज सर्वांगसम हो जाएँ।
\(QR = 6cm,\angle P = {75^o}\)
अतः, सही उत्तर विकल्प (3) है।
Last updated on Jun 25, 2025
-> The SSC CGL Notification 2025 has been released on 9th June 2025 on the official website at ssc.gov.in.
-> The SSC CGL exam registration process is now open and will continue till 4th July 2025, so candidates must fill out the SSC CGL Application Form 2025 before the deadline.
-> This year, the Staff Selection Commission (SSC) has announced approximately 14,582 vacancies for various Group B and C posts across government departments.
-> The SSC CGL Tier 1 exam is scheduled to take place from 13th to 30th August 2025.
-> Aspirants should visit ssc.gov.in 2025 regularly for updates and ensure timely submission of the CGL exam form.
-> Candidates can refer to the CGL syllabus for a better understanding of the exam structure and pattern.
-> The CGL Eligibility is a bachelor’s degree in any discipline.
-> Candidates selected through the SSC CGL exam will receive an attractive salary. Learn more about the SSC CGL Salary Structure.
-> Attempt SSC CGL Free English Mock Test and SSC CGL Current Affairs Mock Test.
-> Candidates should also use the SSC CGL previous year papers for a good revision.
->The UGC NET Exam Analysis 2025 for June 25 is out for Shift 1.