Question
Download Solution PDFयदि (x + \(\rm \frac{1}{x}\)) = 3\(\sqrt2\) है, और x > 1 है, तो (x8 - \(\frac{1}{x^8}\)) का मान कितना है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFप्रयुक्त सूत्र:
(a + b) = a2 + b2 + 2ab.
a8 - b8 = (a4 + b4)(a4 - b4)
गणना
⇒ x + 1/x = 3√2
⇒ (x +1/x)2 = 18
⇒ x2 + 1/x2 + 2 = 18
⇒ x2 + 1/x2 = 16
⇒ (x2 + 1/x2)2 = 162
⇒ x4 + 1/x4 + 2 = 256
⇒ x4 + 1/x4 = 254
⇒ x4 + 1/x4 - 2 = 254 - 2
⇒ (x2 - 1/x2)2 = 252
⇒ x2 - 1/x2 = 6√7
⇒ x8 - 1/x8 = (x4 + 1/x4)(x4 - 1/x4)
= 254 × 16 × 6√7
= 24384√7
सही उत्तर 24384√7 है।
Last updated on Jul 17, 2025
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