Question
Download Solution PDFयदि गोले S1 का पृष्ठीय क्षेत्रफल, गोले S2 से 800% अधिक है, और गोले S2 का आयतन, गोले S1 से x% कम है, तो प्रतिशत के संदर्भ में 'x' का मान कितना है? (दशमलव के दो स्थानों तक पूर्णांकित)
Answer (Detailed Solution Below)
Detailed Solution
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प्रश्न के अनुसार,
⇒ S1 का पृष्ठीय क्षेत्रफल : S2 का पृष्ठीय क्षेत्रफल = 9 : 1
⇒ 4πR 2 : 4πr 2 = 9 : 1
⇒ आर : आर = 3 : 1
⇒ S1 का आयतन : S2 का आयतन = R 3 : r 3
⇒ S1 का आयतन : S2 का आयतन = 3 3 : 1 3
⇒ S1 का आयतन : S2 का आयतन = 27 : 1
S2 का आयतन S1 से कितना प्रतिशत कम है = x %
x% = [(27 -1)/27] × 100 = (26/27) × 100 ≈ 96.29%
∴ सही उत्तर विकल्प (3) है।
Last updated on Jun 30, 2025
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