Question
Download Solution PDFयदि ΔPQR ∼ ΔBAC है, ΔPQR में, PQ = 7 सेमी, QR = (2x - 1) सेमी और ΔABC में, AB = 14 सेमी, AC = (3x + 1) सेमी, तो, QR का मान क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया हुआ है:
ΔPQR ∼ ΔBAC,
ΔPQR में, PQ = 7 सेमी, QR = (2x - 1) सेमी
ΔABC में, AB = 14 सेमी, AC = (3x + 1) सेमी
उपयोग की गई अवधारणा:
यदि ΔPQR ∼ ΔBAC (दोनों त्रिभुज समान हैं)
⇒ PQ / BA = QR / AC = PR / BC
गणना:
∴ PQ / BA = QR / AC
⇒ 7 / 14 = (2x - 1) / (3x + 1)
⇒ ½ = (2x - 1) / (3x + 1)
⇒ 3x + 1 = 4x - 2
⇒ x = 3
∴ QR = (2x - 1) = (6 - 1) = 5 सेमी
Last updated on Jul 18, 2025
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