Question
Download Solution PDFयदि (4x - 7y) = 11 और xy = 8 है, तो 16x2 + 49y2 का मान क्या है, यहाँ x और y धनात्मक संख्याएँ हैं?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
4x - 7y = 11
xy = 8
प्रयुक्त अवधारणा:
(a + b)2 = a2 + b2 + 2ab
गणना:
4x - 7y = 11
⇒ (4x - 7y)2 = 112
⇒ 16x2 + 49y2 - 56xy = 121
⇒ 16x2 + 49y2 - 448 = 121
⇒ 16x2 + 49y2 = 121 + 448
⇒ 16x2 + 49y2 = 569
∴ अभीष्ट उत्तर 569 है।
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