छात्र की ऊँचाई के वितरण के लिए, मोमेंट्स 60.125, 61.345, 62.688 हैं। विषमता का निरपेक्ष माप है:

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SSC CGL Tier-II ( JSO ) 2019 Official Paper ( Held On : 17 Nov 2020 )
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  1. 0.321
  2. 0.312
  3. 0.231
  4. 0.123

Answer (Detailed Solution Below)

Option 4 : 0.123
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दिया है

μ1 = 60.125

μ2 = 61.345

μ3 = 62.688

गणना

विषमता गुणांक βद्वारा दर्शाया जाता है

⇒ β1 = (μ3)2/(μ2)2

⇒ (62.688)2/(61.345)3 

⇒β1 = 0.0170

पूर्ण विषमता माप = γ1

⇒ γ1 = √(β1)

⇒ √(0.0170)

∴ पूर्ण विषमता माप 0.123 है

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